x_{n+1} = x_n + x_n(x_n - 1) / n

I think you have to define x_2 explicitly .. My brain can't comprehend why, but if you use this to find x_2, it returns 1 -- mine did this too (since x_n - 1 = 0 for x_1) ... no idea why.

I wonder since we have two different equations, is it possible to set them equal to eachother and find out anything more interesting.

ms